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PROGRAM TEST
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IMPLICIT NONE
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C
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INTEGER LDA, LDAF, LDB, LDIWRK, LDWORK, LDX, N
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INTEGER NRHS, NSUB, NSUPER
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PARAMETER (N = 4)
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PARAMETER (NSUB = 1)
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PARAMETER (NSUPER = 0)
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PARAMETER (LDA = 2*NSUB + 1 + NSUPER)
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PARAMETER (LDAF = LDA)
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PARAMETER (LDB = N)
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PARAMETER (LDIWRK = N)
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PARAMETER (LDWORK = 3 * N)
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PARAMETER (LDX = N)
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PARAMETER (NRHS = 1)
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C
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DOUBLE PRECISION A(LDA,N), AF(LDAF,N), B(LDB,NRHS)
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DOUBLE PRECISION B1(LDB,NRHS), BERR(NRHS), EPSLON
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DOUBLE PRECISION FERR(NRHS), WORK(LDWORK), X(LDX,NRHS)
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INTEGER ICOL, INFO, IPIVOT(N), IROW, IWORK(LDIWRK)
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C
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EXTERNAL DCOPY, DGBMV, DGBTRF, DGBTRS, DGBRFS
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INTRINSIC ABS, DBLE, MAX
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C
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C Initialize the array A to store in banded form the matrix A
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C shown below. Initialize the array B to store the right hand
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C side vector b shown below.
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C
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C 0 4
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C A = 9 0 b = 4
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C 0.25 5 4
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C 0 70 4
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C
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DATA A / NSUB*8D8, 0.0D0, 9.0D0, NSUB*8D8, 0.0D0, 2.5D-1,
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$ NSUB*8D8, 5.0D0, 0.0D0, NSUB*8D8, 7.0D1, 8D8 /
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DATA B / N*4.0D0 /
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C
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C Add a small value to the elements of A on the diagonal and
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C on the subdiagonal. After this loop, A will contain
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C something similar to:
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C
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C e
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C A = 9+e e
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C 0.25+e 5+e
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C 0+e 70+e
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C
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EPSLON = ((((2.0D0 / 3.0D0) + 8.0D0) - 8.0D0) -
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$ (2.0D0 / 3.0D0))
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DO 110, ICOL = 1, N
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DO 100, IROW = 1, NSUB + 1 + NSUPER
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A(NSUB+IROW,ICOL) = A(NSUB+IROW,ICOL) + EPSLON
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100 CONTINUE
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110 CONTINUE
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CALL DCOPY (LDA*N, A, 1, AF, 1)
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C
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C Print the A array.
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C
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PRINT 1000
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PRINT 1010, A(2,1), 0.0D0, 0.0D0, 0.0D0
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PRINT 1010, A(3,1), A(2,2), 0.0D0, 0.0D0
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PRINT 1010, 0.0D0, A(3,2), A(2,3), 0.0D0
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PRINT 1010, 0.0D0, 0.0D0, A(3,3), A(2,4)
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PRINT 1020
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PRINT 1010, ((A(IROW,ICOL), ICOL = 1, N), IROW = 1, LDA)
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C
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C Make a copy of B and then print B.
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C
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CALL DCOPY (N, B, 1, X, 1)
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PRINT 1030
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PRINT 1040, B
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C
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C LU factor A.
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C
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CALL DGBTRF (N, N, NSUB, NSUPER, AF, LDAF, IPIVOT, INFO)
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IF (INFO .NE. 0) THEN
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PRINT 1050, INFO
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STOP 1
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END IF
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C
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C Solve Ax=b and print the solution.
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C
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CALL DGBTRS ('NO TRANSPOSE A', N, NSUB, NSUPER, NRHS, AF,
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$ LDAF, IPIVOT, X, LDX, INFO)
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IF (INFO .NE. 0) THEN
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PRINT 1060, INFO
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STOP 2
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END IF
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PRINT 1070
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PRINT 1080, X
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CALL DGBMV ('NO TRANSPOSE A', N, N, NSUB, NSUPER, 1.0D0,
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$ A(NSUB+1,1), LDA, X, 1, 0.0D0, B1, 1)
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PRINT 1090
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PRINT 1040, B1
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C
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C Refine the initial solution and print the new solution.
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C
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CALL DGBRFS ('NO TRANSPOSE A', N, NSUB, NSUPER, NRHS,
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$ A(NSUB+1,1), LDA, AF, LDAF, IPIVOT, B, LDB,
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$ X, LDX, FERR, BERR, WORK, IWORK, INFO)
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IF (INFO .NE. 0) THEN
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PRINT 1100, INFO
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STOP 3
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END IF
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PRINT 1110
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PRINT 1080, X
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CALL DGBMV ('NO TRANSPOSE A', N, N, NSUB, NSUPER, 1.0D0,
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$ A(NSUB+1,1), LDA, X, 1, 0.0D0, B1, 1)
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PRINT 1120
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PRINT 1040, B1
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C
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1000 FORMAT (1X, 'A in full form:')
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1010 FORMAT (4(2X, F18.15))
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1020 FORMAT (/1X, 'A in banded form: (* in unused elements)')
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1030 FORMAT (/1X, 'b:')
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1040 FORMAT (1X, F19.15)
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1050 FORMAT (1X, 'Error factoring A in DGBTRF, INFO = ', I5)
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1060 FORMAT (1X, 'Error solving Ax=b in DGBTRF, INFO = ', I5)
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1070 FORMAT (/1X, 'Initial solution for Ax=b:')
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1080 FORMAT (1X, E24.16)
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1090 FORMAT (/1X, 'Ax with initial x:')
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1100 FORMAT (1X, 'Error improving solution in DGBRFS, INFO = ',
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$ I5)
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1110 FORMAT (/1X, 'Refined solution for Ax=b:')
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1120 FORMAT (/1X, 'Ax with improved x:')
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C
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END
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