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PROGRAM TEST
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IMPLICIT NONE
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C
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DOUBLE PRECISION ZERO
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INTEGER LDA, LDB, LDWORK, N, NRHS
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PARAMETER (N = 3)
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PARAMETER (LDA = N)
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PARAMETER (LDB = N)
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PARAMETER (LDWORK = 1)
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PARAMETER (NRHS = 1)
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PARAMETER (ZERO = 0.0D0)
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C
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COMPLEX*16 A(LDA,N), B(LDB,NRHS), WORK(LDWORK)
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INTEGER ICOL, INFO, IPIVOT(N), IROW
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C
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EXTERNAL ZHESV
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INTRINSIC ABS, CMPLX, CONJG, DBLE
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C
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C Initialize the array A to store the coefficient array A
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C shown below. Initialize the array B to store the right
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C hand side vector b shown below.
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C
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C 1 1-i 1-i 4+i
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C A = 1+i 3 3-i b = 4+6i
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C 1+i 3+i 5 4+7i
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C
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DATA A / (1.0D0,8D8), (8D8,8D8), (8D8,8D8),
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$ (1.0D0,-1.0D0), (3.0D0,8D8), (8D8,8D8),
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$ (1.0D0,-1.0D0), (3.0D0,-1.0D0), (5.0D0,8D8) /
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DATA B / (4.0D0,1.0D0), (4.0D0,6.0D0), (4.0D0,7.0D0) /
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C
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C Print the initial value of the arrays.
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C
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PRINT 1000
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DO 100, IROW = 1, N
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PRINT 1010, (CONJG(A(ICOL,IROW)), ICOL = 1, IROW - 1),
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$ CMPLX(DBLE(A(IROW,IROW)), ZERO),
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$ (A(IROW,ICOL), ICOL = IROW + 1, N)
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100 CONTINUE
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PRINT 1020
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DO 110, IROW = 1, N
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PRINT 1010, (A(IROW,ICOL), ICOL = 1, N)
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110 CONTINUE
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PRINT 1030
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DO 130, ICOL = 1, NRHS
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DO 120, IROW = 1, N
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PRINT 1010, B(IROW,ICOL)
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120 CONTINUE
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130 CONTINUE
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C
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C Compute and print the solution.
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C
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CALL ZHESV ('UPPER TRIANGLE OF A STORED', N, NRHS, A, LDA,
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$ IPIVOT, B, LDB, WORK, LDWORK, INFO)
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IF (INFO .LT. 0) THEN
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PRINT 1040, ABS(INFO)
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STOP 1
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ELSE IF (INFO .GT. 0) THEN
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PRINT 1050
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STOP 2
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END IF
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PRINT 1060
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DO 210, ICOL = 1, NRHS
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DO 200, IROW = 1, N
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PRINT 1010, B(IROW,ICOL)
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200 CONTINUE
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210 CONTINUE
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C
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1000 FORMAT (1X, 'A in full form:')
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1010 FORMAT (1X, 10(: 2X, '(', F4.1, ',', F4.1, ')'))
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1020 FORMAT (/1X, 'A in Hermitian form: (* in unused entries)')
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1030 FORMAT (/1X, 'b:')
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1040 FORMAT (1X, 'Illegal argument to ZHESV, argument #', I2)
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1050 FORMAT (1X, 'A is singular to working precision.')
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1060 FORMAT (/1X, 'x:')
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C
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END
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